A1065

1065 A+B and C (64bit) (20分)

Given three integers A, B and C in [−2 ​63 ​​ ,2 ​63 ​​ ], you are supposed to tell whether A+B>C.

Input Specification:
The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:
For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

用long double可以直接过

#include<iostream>
#include<string>
#include<vector>
#include<map>
#include<set>
#include<queue>
#include<cstdio>
#include<algorithm>
using namespace std;
int main(){
    int n;
    long double a,b,c;
    cin>>n;
    for(int i=1;i<=n;i++){
        cin>>a>>b>>c;
        cout<<"Case #"<<i;
        if(a+b<=c)cout<<": false"<<endl;
        else cout<<": true"<<endl; 
    }
    return 0;
}